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Mathematics 15 Online
OpenStudy (anonymous):

6x – 5y > –35 3x + y ≤ 2 (4, 7) (–2, 3) (6, –5) (–9, 2)

jimthompson5910 (jim_thompson5910):

Simply plug in each point and see if the inequalities are true. For instance, for (4,7) x=4 and y=7 6x – 5y > –35 6(4) – 5(7) > –35 24-35 > –35 -11 > -35 ... true 3x + y ≤ 2 3(5) + 7 ≤ 2 15+7 ≤ 2 22 ≤ 2 ... false Since the last inequality is false, (4,7) is NOT in the solution set. I'll let you keep going and try the others.

hero (hero):

Yes, that's the right approach

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