Question

solve for x
\[8^{x-1} = 2^{x+1}\]

Answer 1

replace 8 with 2^3 and go from there...

Answer 2

0.o?

Answer 3

\[2^{3^{x-1}} = 2^{x+1}\] ?

Answer 4

rule of exponents i mean

Answer 5

Pretty close. 3*(x-1) not 3x-1

Answer 6

it's not 3^x-1?

Answer 7

\[(2^{3})^{x-1}= 2^{3(x-1)}\]

Answer 8

wait I seem to remember if the bases are the same ( both 2) then it should just be
3(x-1) = x+1 right?

Answer 9

yes.

Answer 10

x=2?

Answer 11

Yes. But you can (and should) check it. plug 2 into the original problem

Answer 12

gives me 8 = 2 :(

Answer 13

oh wait

Answer 14

hey it's right!

Answer 15

thanks phi!