Question

solve for y:

(x+2)^2+(y-3)^2=25

Answer 1

\[\large (x+2)^2+(y-3)^2=25\]



\[\large (y-3)^2=25-(x+2)^2\]



\[\large y-3=\pm\sqrt{25-(x+2)^2}\]



\[\large y=\pm\sqrt{25-(x+2)^2}+3\]

Answer 2

really? this is a circle with center (-2,3) and radius 5

Answer 3

will get two solutions

Answer 4

oh jimthompson has it worked out

Answer 5

So you basically have two equations \[\large y=3+\sqrt{25-(x+2)^2}\]


\[\large y=3-\sqrt{25-(x+2)^2}\]