How do you solve a quartic equation by hand?
substitution
a^4 = x^2
If it's a trinomial, that works perfectly
Then you could just use quadratic equation or maybe it will be factorable....Depends...
There's other methods too. Sometimes , substitution doesn't give you the right form when you find x.
hmmm...well, for example...\[x^4-15x^2-6x+(73-r^2)\] where r is a constant
I've seen this before. It's like the whole \[x^4-15x^2-6x \] becomes c value
So you're supposed to use quadratic formula
I wish I'd saved this in geogebra.
lol I'm pretty confused :/
If I were you, I'd be confused too
Hold on, looks like I was smart enough to save the previous one afterall...
Yeah, you have to use quadratic formula. I don't recommend trying to solve this by any other means....
It doesn't tell you what to solve for, does it?
Would help to post the full set of instructions
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