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Write the equation of the line with slope 5/3 which passes through the point (3, -2).
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Yokieee can u answer on my question :P
y-y1=m(x-x1), in this case m=5/3 and (x1,y1)=(3,-2)
you have to plug the numbers into the formula
totally wrong :P
it should look like this: y-(-2)=5/3(x-3), now just evluate that
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is this right y = (5/3)x + 3
you got the slope right
y + 2 = 5/3x +3
but check the arithmetic
wait..did that wrong lol
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y=5/3x-7
y + 2 = 5/3(x - 3)
y + 2 = 5/3x -5
y = 5/3x - 7
there we go
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yup i got the same answer y=5/3x-7
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