Question

how would you solve sin^2 (pi/4) - cos^2 (pi/3)

Answer 1

\[\sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}, \cos(\frac{\pi}{3})=\frac{1}{2}\]

Answer 2

use that just plug in

Answer 3

one ten or two twenty?

Answer 4

do what?

Answer 5

\[(\sin(\frac{\pi}{4}))^2-(\cos(\frac{\pi}{3}))^2\]
is what you have
just plug in the numbers I gave you above
you can find these numbers on your handy dandy trig cheat cheat

Answer 6

*sheet

Answer 7

shhh
lol

Answer 8

:)

Answer 9

like that one

Answer 10

do you understand to do this:
\[(\frac{\sqrt{2}}{2})^2-(\frac{1}{2})^2\]

Answer 11

so i ignore the square sign, solve for what's inside the parentheses then square the answer?

Answer 12

oh no! square, then subtract. just like it is written

Answer 13

so that would be 2/4 - 1/4

Answer 14

yup

Answer 15

yes

Answer 16

on the 4th post above i ment what u put up earlier