Question

Solve by completing the square
x^2-14x=10

Answer 1

take half the coefficent of -14, it should be -7. The we have (x-7)^2 which equals=x^2-14x+49. That means you get: (x-7)^2=59

Answer 2

or (x-7)^2-59=0

Answer 3

\[\large x^2-14x=10\]


\[\large x^2-14x-10=0\]


\[\large x^2-14x+49-49-10=0\]


\[\large (x-7)^2-49-10=0\]


\[\large (x-7)^2-59=0\]


\[\large (x-7)^2=59\]


\[\large x-7=\pm\sqrt{59}\]


\[\large x=7\pm\sqrt{59}\]

Answer 4

x=7plus or mius sqrt59

Answer 5

\[x^2-14x=10\]
\[(x-7)^2=10+7^2=59\]
\[x-7=\pm\sqrt{59}\]
\[x=7\pm\sqrt{59}\]

Answer 6

good