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4√y-3=2
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13/4
Assuming it's \[4\sqrt{y-3}=2\] \[4\sqrt{y-3}=2\] \[4^2(y-3)=2^2\] \[16(y-3)=4\] \[y-3=\frac{4}{16}\] \[y-3=\frac{1}{4}\] \[y=\frac{1}{4}+3\] \[y=\frac{13}{4}\]
is this similified?
no the answer was 19
What was the the original problem, was it \[4\sqrt{y-3}=2\] ???
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oh wait, if the answer is 19, then the problem has to be \[\sqrt[4]{y-3}=2\] am I correct in saying that?
yes
\[\large \sqrt[4]{y-3}=2\] \[\large y-3=2^4\] \[\large y-3=16\] \[\large y=16+3\] \[\large y=19\]
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