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Mathematics 19 Online
OpenStudy (anonymous):

4√y-2=3

jimthompson5910 (jim_thompson5910):

Is the problem \[4\sqrt{y-2}=3\]??? Just checking before I start.

OpenStudy (anonymous):

yeah that is it

jimthompson5910 (jim_thompson5910):

ok thx \[4\sqrt{y-2}=3\] \[\sqrt{y-2}=\frac{3}{4}\] \[y-2=(\frac{3}{4})^2\] \[y-2=\frac{9}{16}\] \[y=\frac{9}{16}+2\] \[y=\frac{41}{16}\]

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