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Mathematics
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Integrate (2 ln x)/x
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do a u substitution. Let: \[u = \ln(x)\]
\[\int\limits_{}^{}\frac{2lnx}{x}dx = ?\]
put \(t = lnx\) then you have \(dx = dtx\)
take lnx=u you will get dx=dt/x
oh
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then the integral becomes \(2\int t dt\)\[2\frac{t^2}{2} + C\]
\[\int\limits_{}^{}\frac{2\ln x}{x}dx = 2 \int\limits_{}^{}\ln x \frac{1}{x} dx \] substitute with\[u = \ln x\] how do we get \[\int\limits_{}^{}udu\] ?
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