Question

I'm trying to solve the quadratic equation f(x)= -2(x +2)^2 but I don't know how to use the form ax^2+bx+c without the +c, can someone explain? please

Answer 1

right now its in vertex form
you have to expand to get it into standard form

Answer 2

I have to find the vertex

Answer 3

(x+2)^2 = (x+2)(x+2)
distribute

Answer 4

oh nevermind, then its easy

Answer 5

you have it in vertex form
\[f(x)=a(x-h)^2+k, V(h,k)\]

Answer 6

\[f(x)=-2(x+2)^2+0\]

Answer 7

identify what h and k are
and you are done

Answer 8

ok, just make it 0, it's that easy, thank you