Show all work. A disc jockey has 10 songs to play. Seven are slow songs, and three are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 10 songs if
The songs can be played in any order.
The first song must be a slow song and the last song must be a slow song.
The first two songs must be fast songs.

Question

Show all work. A disc jockey has 10 songs to play. Seven are slow songs, and three are fast songs.  Each song is to be played only once.  In how many ways can the disc jockey play the 10 songs if 
The songs can be played in any order. 
The first song must be a slow song and the last song must be a slow song. 
The first two songs must be fast songs.

anonymous · Answer

any order 10!

anonymous · Answer

oops i had slow and fast backwards.

anonymous · Answer

huh!

anonymous · Answer

i screwed up on #2 not i have to think.

anonymous · Answer

zarkon?

anonymous · Answer

7 for the first, 6 for the last, and 8*7*6*5*4*3 for the middle so i think it is 
7*6/8*7*6*5*4*3

anonymous · Answer

How can the first song be both fast and slow?

anonymous · Answer

first two slow
3*2 then 8*7*6*5*4*3

zarkon · Answer

is there a reason you are dropping the 2?

zarkon · Answer

$$10!$$
$$_7P_2\cdot 8!$$
$$_3P_2\cdot 8!$$

anonymous · Answer

i have no clue what yall are doing please explain!

zarkon · Answer

$$_7P_2=7\times 6$$

$$_3P_2=3\times 2$$

zarkon · Answer

1) 3628800
2) 1693440
3) 241920

anonymous · Answer

ok so it was right yes? i mean what i wrote

anonymous · Answer

oh no it was wrong. i didn't put the 2 at the end. doh

anonymous · Answer

first two slow 3*2 then 8*7*6*5*4*3*2
so 
3*2*8*7*6*5*4*3*2

anonymous · Answer

i would like to think that was a typo

zarkon · Answer

I would too

anonymous · Answer

lol!