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Simplify by removing the factors of 1. z^2-16/4-z
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Im getting (z-4)(z+4)/(z-4) but I think I am missing a step
You swapped the negative in your denominator. Which you can do (and need to in order to cancel properly) but you have to factor out a -1 in order to make it work. \[\frac{(z+4)(z-4)}{4-z} = \frac{(z+4){(z-4)}}{-1(z-4)} = -1(z+4) = -z-4 \text{ , } z \ne 4 \]
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