g(x)=log(x+5) and g(x)=log(-x)
for g(x)=log(x+5) all that we're doing is taking f(x)=log(x) and shifting it 5 units to the left
for the second function, we're starting with the graph of f(x)=log(x) and reflecting it over the y-axis to get the graph of g(x)=log(-x)
equation of the vertical asymptotic
y intercept in (x,y) form
the equation of the vertical asymptote for g(x)=log(x+5) is x = -5 since this makes the argument equal to zero. The x-intercept is (-4,0)
the equation of the vertical asymptote for g(x)=log(-x) is x = 0 since this makes the argument equal to zero. The x-intercept is (-1,0)
\[g(x)=\log(x+5)\] Equation of the vertical Asymptote: X-intercept in (x,y) form:
g(x) = log(x+5) Equation of the vertical Asymptote: x = -5 X-intercept in (x,y) form: (-4,0)
g(x) = log(-x) Equation of the vertical Asymptote: x = 0 X-intercept in (x,y) form: (-1,0)
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