Mathematics
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OpenStudy (anonymous):
3x^2 + 8x + 2 = 0
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hero (hero):
Yo!
hero (hero):
I'll have it solved here in just a sec
OpenStudy (anonymous):
thats because you are pro! and i've been trying to remember the formula you gave me.
hero (hero):
\[ac = (\frac{b}{2}+d)(\frac{b}{2}-d)\]
hero (hero):
Solve for d
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hero (hero):
You can also just use the quadratic formula
OpenStudy (anonymous):
Whats the formula for that?
hero (hero):
\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]
hero (hero):
Just input a = 3, b = 8, c = 2 into the equation and solve for x
OpenStudy (anonymous):
How do i do a and c? do i combine them together? or..?
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hero (hero):
yes, when you see ac it means the values of a and c are multiplied
OpenStudy (anonymous):
right now i have .. \[x=-8 \pm \sqrt{40} \] / 6
OpenStudy (anonymous):
is that right?
hero (hero):
looks right...hold on
OpenStudy (anonymous):
okay..
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hero (hero):
Yes, it is correct
hero (hero):
You just have to simplify it further
hero (hero):
\[x = \frac{-8 \pm \sqrt{40}}{6} = \frac{-4 \pm \sqrt{10}}{3}\]
hero (hero):
There ya go
hero (hero):
Good job on solving it yourself
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OpenStudy (anonymous):
Thanks to you! Thank you!(:
OpenStudy (anonymous):
But yet. Im still confused on what is the answer o.o
hero (hero):
That IS the answer
hero (hero):
I just simplified it further for you
hero (hero):
All you were supposed to do is solve for x. You did that
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OpenStudy (anonymous):
And x =..? o.o
hero (hero):
Look up....
hero (hero):
\[x = \frac{-8 \pm \sqrt{40}}{6} = \frac{-4 \pm \sqrt{10}}{3} \]
hero (hero):
notice how it says x = .....
hero (hero):
that is the form you would write it in having used the quadratic formula
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OpenStudy (anonymous):
And how would it be the other way? And Oh i get it now.. ~for the quadratic formula
hero (hero):
It would be the same way the other way....but like this:
\[(x + \frac{4 + \sqrt{10}}{3})(x + \frac{4 -\sqrt{10}}{3}) \]
hero (hero):
You just have to work with these a little more to understand
OpenStudy (anonymous):
oh okay o.o
OpenStudy (anonymous):
oh okay o.o