Question

hello, i do have te answers but i'd like to make sure i have this right before graphing the circle. and thank you in advance for your help.

*a circle has the equation 3(x-4)^2+3y^2=27 Find the center (h,k) and radius r.

*Then find the intercepts, if any, of the graph.

Answer 1

(h,k) = (4,0)

Answer 2

r = sqrt{27} or 3sqrt{3}

Answer 3

good

Answer 4

Need to bring the 3 out.

\[r = \sqrt{27/3}\]

r =3

Answer 5

Hello Hero and Nilanshki, yes, I have the same exact answer and had plotted the circle but I was worried I was worried. I'm new to this forum...glad we can all help each other here. Thanks so much for helping me by confirming it.

Answer 6

I meant I was worried about not getting the right answer. lol. thnaks again.

Answer 7

"Need to bring the 3 out."
By which i mean

3(x-4)^2+3y^2=27

3((x-4)^2+y^2)=27

(x-4)^2+y^2= 9 (27/3)

Answer 8

Hi Dangolbery, SOunds great. I actually have the answers written down before asking...just had to make sure. Thanks so much for your help too.

Answer 9

i'm doing the problems by hand cause i can't figure out y new calculator yet. glad we have this site. you guys are awesome!

Answer 10

good