5x^2 + 3x - 16 = 0

Question

5x^2 + 3x - 16 = 0

chaise · Answer

Quadratic formula.
a = 5
b = 3
c = -16

(-b +/- sqrt(b^2-4ac))/2a

Sub in your numbers and you should get two outcomes. Do you need me to explain further?

mimi_x3 · Answer

Use the quadratic formula ,
x = 1.14 , x = -1.74568

hero · Answer

maz5tl, you know how to do these.

anonymous · Answer

i got . $$-1\sqrt{3-32}$$ / 1 thought i think that is wrong..

mimi_x3 · Answer

Yeah , it is wrong because there cannot be a minus in a square root

anonymous · Answer

wait its a plus because -16 i forgot!

anonymous · Answer

$$x = -1 \sqrt{3 + 32}$$ /1 is that wrong too? or right?

mimi_x3 · Answer

You should have got 
$$-3 \pm \sqrt{329} / 10$$

anonymous · Answer

oh. how do i get that?

mimi_x3 · Answer

hm , use the quadratic formula and substitute a , b and c

hero · Answer

Mimi is correct, however, her fraction is still written incorrectly

hero · Answer

$$x = \frac{-3 \pm \sqrt{329}}{10}$$

hero · Answer

Write it like that in order to avoid the linear mistake

chaise · Answer

I hate to rudely but in randomly; Hero can you show me how to put one equation on another in the equation editor?
Thanks in advance.

hero · Answer

x = \frac{-3 \pm \sqrt{329}}{10}

hero · Answer

If that makes any sense

hero · Answer

frac{a}{b}

hero · Answer

put that in equation editor to get this: 
$$\frac{a}{b}$$