Question

How do I find the x and y intercepts for y=4(x-2)squared

Answer 1

set x = 0
y = 4 * (0-2) = -8

set y = 0
0 = 4(x-2)^2
0 = (x-2)^2
x = 2

Answer 2

when solving x what happened to the 4?

Answer 3

you divide both sides by 4 and 0 divided by 4 is 0

Answer 4

Also in finding y what happened to the square? y=4(x-2)^2

Answer 5

nothing, it means that the curve just touches the x axis instead of intersecting it twice. draw it out, there are online autographs available and you'll know what i mean.

Answer 6

I worked it out as below. Where have I gone wrong

y=4*(0-2)^2
y=4*(0-2)(0-2)
y=-8 -2
y=16

Answer 7

you are right, i forgot about the squared bit

Answer 8

Thanks heaps for your help