the "table" shows the change in population for a group of mice over a 4 month period.

month: 0 1 2 3 4
pop: 2 8 16 32 64

if this pattern continues, what wll be the population of mice in month 12?
a) 192 b) 4096 c) 8192 d) 16384

Question

the "table" shows the change in population for a group of mice over a 4 month period.

month: 0  1  2   3    4
pop:     2  8 16 32 64

if this pattern continues, what wll be the population of mice in month 12? 
a) 192   b) 4096   c) 8192   d) 16384

amistre64 · Answer

2 8 16 32 are the 2^n stuff

amistre64 · Answer

2^0 = 1

so 2^(n+1) looks like a better fit

anonymous · Answer

what?

amistre64 · Answer

did i miss it again?  :)

anonymous · Answer

no, i just dont get it

amistre64 · Answer

2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16

amistre64 · Answer

month 0 = 2^(0+1) = 2
month 1 = 2^(1+1) = 4  that one dont fit

anonymous · Answer

but how does that go with the problem?

anonymous · Answer

oh, i think i get it now

amistre64 · Answer

if it wasnt for month 1 being 8, itd fit good so I think we might need to ignore that one bad fit

amistre64 · Answer

unless there is a typo in the question :)

anonymous · Answer

0 doesnt fit either. i dont think that thats it

anonymous · Answer

no, no typo

amistre64 · Answer

month 2 = 2^(2+r) = 16
             = 2^(2+2) = 16
             = 2^(n+2)

month 12 = 2^(12+2) = 2^14 = 16384  perhaps?

anonymous · Answer

oh, maybe. ill just ask my teacher tho, thanks!

amistre64 · Answer

k, good luck with it