Question

p=mv^2 prove this is dimensionally incorrect

Answer 1

p is momentum?

Answer 2

Yeah

Answer 3

i doubt it

Answer 4

it was in last yr paper

Answer 5

yes it is momentum

Answer 6

hey guys tmrw i hav exam

Answer 7

p=mv is the equation, so that "proves" it.

Answer 8

and it should be mv

Answer 9

wel show

Answer 10

why it is dimensionally incorrect

Answer 11

the dimensions of p can be found out by using the original formula mv.....
as there is a v more on RHS it is dimensionally incorrect

Answer 12

what does xchess have to say?

Answer 13

k
find no of significan figure in .5100

Answer 14

i believe 4

Answer 15

wait 4 or 2

Answer 16

2

Answer 17

For the p=mv^2 disproof, I guess you could say velocity varies inversely with mass in conservation of momentum...

Answer 18

which of foll represent time displacement graph of 2 objects moving with 0 relative velocity?????

Answer 19

"Dimensionsal analysis" is just a way of stripping out the numbers in a complicated equation and seeing if the units are the same on either side. We use [M] for mass, [L] for length, and [T] for time.

So Velocity is a distance divided by a time, and so we say [L][T]^-1

?? p=mv^2
The dimensions of momentum are [M][L][T]^-1
The dimensions of mv^2 are [M][L]^2[T]^-2

As these are not the same, the equation is dimensionally incorrect.

One can actually choose whatever dimensions one wants but the above are the usual ones. We also use [Q] for electrical charge and [theta] for temp.