find the equations for the asymptotes of the hyperbola (x^2)/36 - (y^2)/5 = 1 please explain in detail?

Question

amistre64 · Answer

the bottom give you the measure of a^2 and b^2 in a standard hyper notation

amistre64 · Answer

the slope of the asymptote is y/x, or in this case sqrt(5)/sqrt(36) and it goes thru the point (0,0) since its centerd at zero

amistre64 · Answer

x^2/a^2 - y^2/b^2 = 1

(x/a)^2 - (y/b)^2 = 1

(under y)/(under x) = slope  right?

amistre64 · Answer

anonymous · Answer

lol im still trying 2 unerstand but thnx 4 th help

amistre64 · Answer

practice helps :)