Question

12x^2+4x-1
------------
2x+1

Answer 1

Set something up like this:
(2x+1) ( )
What goes on the far right to get 1*x = -1?

Answer 2

That gives you
(2x+1) ( - 1)
2x * -1 + (1 * Nx) = 4x.
WHat is n?

Answer 3

2?

Answer 4

6x(2x+1)(2-1)?

Answer 5

Here set it up like this:
(2x+1)(Nx + y)

The constant term of the result is -1, and you get the constant part by multiplying the last term of each binomial, so that gives:
1*y = -1
You solve for y to get -1
Now write
(2x+1)(Nx + y)
The x^2 part of the result is 12x^2, and you get the x^2 part by multiplying the first term of either binomial, so that gives:
2x*Nx = 12x^2 Solve for N.

Or, like I was showing before, you get the x part of the result by:
2x*-1 + 1*Nx = 4x. Solve for N.

Doing either of the last 2 should give you the right value for N.

Answer 6

6x-1 is the answer right? the 2x+1 cancels out and 6x-1 is left ?