how do i find the distance between these pairs of points: (-2,-2).. (-4,-1)?
please walk me through it
\[\sqrt{(x-x2)(y-y2)}\]
in english, the distance between -2 and-4 on the x axis is 2 the distance between -2 and-1 on the y axis is 1 pythatoras tells you that \[d^2=2^2+1^2=4+1=5\] so \[d=\sqrt{5}\]
d=sqrt[(x2-x1)^2+(y2-y1)^2]
@math pro and zbay u forgot exponents
you can use the formula \[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] but just make sure you 1) subtract 2) square 3) add 4) take the square root
yes
lol sorry dont mean to be mean
@satellite in that order? and everyone thanks for the help :)
if u just plug the whole thing in caclulator it will work just fine too :P
if you want to use the formula here you can write \[\sqrt{(-2-(-4))^2+(-2-(-1))^2}\] \[\sqrt{2^2+1^2}\] \[\sqrt{4+1}\] \[\sqrt{5}\]
thanks everyone!!!!!
first subtract in each coordinate. be careful of the signs, and make sure you are subtracting x's from x's and y's from y's
then square each one then add then take the square root. don't try any shortcuts!
thanks
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