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Prove sqrt(3) is irrational.
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it doesnt have real roots.
how will u prove it, without using calculator
Also, there is an actual proof...
ye, and thats what
Okay, but I demand a fanship and a medal, because it's tedious to write.
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lol nevermind :P
WELL FINE THEN. :P
you want an actual proof right?
as usual with such proofs start with assuming the contrary, that \[\sqrt{3}=\frac{a}{b}\] with a, b integers. the square and get \[3=\frac{a^2}{b^2}\iff 3b^2=a^2\]
I was going to give him Euclid's Proof too, but he didn't want it....
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now appeal to the fundamental theorem of arithmetic, and factor a and b as the product of primes.
oh then i will be quiet
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