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OpenStudy (anonymous):
hmn,
OpenStudy (anonymous):
i don't think that u r correct satellite , why u wrote sqrt_{a} and sqrt_{b}
OpenStudy (anonymous):
who solved this myinianya ?
myininaya (myininaya):
i solved it in that pdf
OpenStudy (anonymous):
myinianya do u have scanner
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myininaya (myininaya):
yes
OpenStudy (anonymous):
how ? , is there any software
OpenStudy (anonymous):
exponentiate both sides get
\[\frac{1}{3}(a+b)=e^{\log(\sqrt{a})+{\log(\sqrt{b})}}\]
\[\frac{1}{3}(a+b)=e^{\log(\sqrt{a})}\times e^{{\log(\sqrt{b})}}\]
myininaya (myininaya):
doesn't everyone
lol
i don't my husband does all the computer stuff that makes me happy
myininaya (myininaya):
interesting satellite i didn't go that route
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OpenStudy (anonymous):
ok , u r my aunt . i am only 13 years old
OpenStudy (anonymous):
so
\[\frac{1}{3}(a+b)=\sqrt{a}\sqrt{b}\] or
\[(a+b)=3\sqrt{a}\sqrt{b}\]
myininaya (myininaya):
you aunt ?
OpenStudy (anonymous):
square both sides get
\[a^2+b^2+2ab=9ab\]
OpenStudy (anonymous):
so
\[a^2+b^2=7ab\]
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OpenStudy (anonymous):
THERE DID IT!
OpenStudy (anonymous):
no , i meant that u r my aunt .
OpenStudy (anonymous):
thanks satellite , u r much different
myininaya (myininaya):
how do you know me?
how are we related?
myininaya (myininaya):
i'm confused
is satellite your uncle?
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OpenStudy (anonymous):
sorry it took so long to type in
OpenStudy (anonymous):
I don't know u . i meant that u r of age of my aunt :)
OpenStudy (anonymous):
yeah kush is the son of a sister my mother never had
OpenStudy (anonymous):
satellite u r gr8 . thanks very much
myininaya (myininaya):
im 26
you make me sound old by calling me your aunt
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