Question

what is the eqation to the line parrallel to line 2x-y=-2 given point (6,0)?

Answer 1

y = 2x + 2

y = 2x - 12

Answer 2

2x-y=12

Answer 3

there is only one possible answer.

Answer 4

Yeah, the first eqn is just me rearranging the given equation into something useful.

Second eqn is the answer. Same as yours.

Answer 5

I see.

Answer 6

whre does the -12 come from?

Answer 7

You want the second equation to be parallel so the gradient needs to be maintained. The gradient being the 2x so you know the second eqn must look like

y = 2x + b

Where b still needs to be figured out.

Sub in the given coordinate (6,0) into this new equation and solve for b.

0 = 2*(6) + b
b = 0 - 12
b = -12

Answer 8

Well to be padantic the gradient is just the 2 infront of the x.

Answer 9

The general equation of a line is

y = mx + b

Where;
m = gradient (or the slope of the line, rise/run, y/x)
b = the y-intercept (the location on the graph where the line crossing the y axis)
With x and y being input variables x and y.

If a line is to run parallel to another line the slope has to be the same, otherwise they would cross at some point and hence not be parallel.