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polpak help me : u said that log(1+2+3) = log1+ log2+ log3 only in this case . my question is : can this be proved ?
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what is log 6?
I'l prove it with a calculator =P
polpak said me that log(1+2+3) = log 6 or log1+log2+log3 , but only for the case of 1 , 2 and 3 he said that i am asking , that can it be proved
if its only for this case then calculation suffices as proof
log6=log(1*2*3) =log1+log2+log3
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that's the proof
1+2+3=1*2*3
yes log6=log(1+2+3)
that is the Product rule
In this case or in any case dealing with log 1 you can do so this because in the product rule expansion you will get log 1 as 0
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