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7/5N + 3/5= -N HOW TO WORK
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multiply by 5, subtract by 3, add by 5N, combine like terms, and divide off the 12 perhaps
\[\frac{7}{5}N+\frac{3}{5}=-N\] \[\frac{7(5)}{5}N+\frac{3(5)}{5}=-(5)N\] \[7N+3-3=-5N-3\] \[7N+5N=-3\] \[12N=-3\] \[\frac{12N}{12}=\frac{-3}{12}\] \[N=-\frac{3}{12}=-\frac{1}{4}\]
algebra is alot like shuffling cards
why didnt the 3(5) make it 15?
becasue 5/5 = 1 in the end of it. but dont let that confuse you; we could have gone thru that step just as well. \[\frac{3(5)}{5}=\frac{15}{5}=3\]
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ok i am still skipping steps
just take practice :)
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