Correction to my original problem:
36x^3 + x^2 - 21x = 0
I had it set to 2nd degree at first.
Needs to be factored to solve.

Question

Correction to my original problem: 
36x^3 + x^2 - 21x = 0 
I had it set to 2nd degree at first.
Needs to be factored to solve.

radar · Answer

x(36x^2 + x - 21)
x(9x+7)(4x-3)=0
x=0
x=-7/9
x=3/4

anonymous · Answer

How did you get the second line? I see that they are broken down from 36x^2 and - 21, but I thought that you have to solve by getting the product of 36 and 21 and find number that multiply to the product and add to 1. Thanks

radar · Answer

Your thoughts were correct the product of 9 and 4 is 36.
The combination of (28x and -27x) does = x . the 28x is the result of 7 times 4x, the -27x is the result of 9x times -3.

anonymous · Answer

Yeah, I figured it out right after I asked you. Thank you for your help though. 
I really appreciate it!