Question

A collection of 27 coins, all nickels and dimes, is worth $2.10. How many of each coin are there?

Answer 1

5n+10d=210

Answer 2

n=number of nickels, d=number of dimes

Answer 3

no because there is a total of 27 coins, not 15.

Answer 4

missed that part .. hang on :)

Answer 5

We need to solve this :
n+d=27
5n+10d=210

Answer 6

d=27-n
5n+10(27-n)=210
5n+270-10n=210
-5n=-60
n=12
d=27-n=27-12=15

so there are 12 nickels and 15 dimes

Answer 7

and here are the 27 coins :)

Answer 8

yayy! :) thank you so much...Btw i was trying to figure it out too.

Answer 9

np :)

Answer 10

n = (2.10 - 27(.10))/(.05-.10)

d = (2.10 - 27(.05))/(.10-.05)

Answer 11

so yeah, 12 ns and the rest are ds :)