Question

use sqrt property to solve:
(4k-1)^2+28=1
k=??

Answer 1

\[\large (4k-1)^2+28=1 \]



\[\large (4k-1)^2=1-28 \]



\[\large (4k-1)^2=-27 \]



\[\large 4k-1=\pm\sqrt{-27}\]



\[\large 4k-1=\sqrt{-27} \ \ \textrm{or} \ \ 4k-1=-\sqrt{-27}\]



\[\large 4k-1=3i\sqrt{3} \ \ \textrm{or} \ \ 4k-1=-3i\sqrt{3}\]



\[\large 4k=1+3i\sqrt{3} \ \ \textrm{or} \ \ 4k=1-3i\sqrt{3}\]



\[\large k=\frac{1+3i\sqrt{3}}{4} \ \ \textrm{or} \ \ k=\frac{1-3i\sqrt{3}}{4}\]

Answer 2

oh hey!! the page didn't show this for me! You rock :)

Answer 3

yeah the messaging system is a bit weird for me too