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3(n+1)! divided by 5n!
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Please help, I need a good grade on my summer math packet.
or this
Do you think you could explain it, please?
the answer is 3(n+1)/5
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\[\frac{3(n+1)!}{5n!}=\frac{3(n+1)n!}{5n!}=\frac{3(n+1)\not{n!}}{5\not{n!}}=\frac{3(n+1)}{5}\]
(n+1)! = (n+1)(n)(n-1)...(3)(2)(1) n! = (n)(n-1)...(3)(2)(1) Notice how both have the terms (n)(n-1)...(3)(2)(1) in common, so they cancel.
and they leave the term n+1 behind
ie \[\frac{(n+1)!}{n!}=n+1\]
\[\cos(\sin^{-1} 1/2)\]
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What about this one? I'm not sure where to start.
make a right triangle
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