Question

Write the expression as a complex number in standard form. Here is the problem 4i(3-i)(-2+8i)

Answer 1

-104+8i

Answer 2

\[-104 + 8i\]

Answer 3

I have to break the problem down
I see how you got that answer. I just need to see it broken down.

Answer 4

Okay. Use the distributive property. You have:
\[4i(3-i)(-2+8i)\]
Firstly distribute through the 4i:
\[((3)(4i)-(i)(4i))(-2+8i)=(12i-4i^2)(-2+8i)\]
But you know that:
\[i^2=(\sqrt{-1})^2=-1\]
So:
\[(12i-4(-1))(-2+8i)=(12i+4)(-2+8i)\]
Now, call: A=(12i+4) giving:
\[A(-2+8i)\]
Now distribute:
\[-2A+8iA\]
But A=12i+4:
\[-2(12i+4)+8i(12i+4)=-24i-8+96i^2+32i=-24i-8-96+32i=-104+8i\]

Answer 5

That a good explanation?

Answer 6

Thank you malevolence19

Answer 7

No problem xPPP