Question

why sin1/x is treated as bounded function?

Answer 1

think about the values c cannot be?

Answer 2

i mean x

Answer 3

now compare it to a normal sinx graph

Answer 4

because even though 1/x is unbounded when approaching 0, the sine function itself is bounded.

Answer 5

hey joemath

Answer 6

\[\sin(junk)\] will always be bounded

@hahd yo :)

Answer 7

@joe come on chat

Answer 8

If you think about sin as the \(y\) component of an arm on a unit circle, regardless of the angle the \(y\) component will always be between \(-1\) and \(1\)

Answer 9

So the function is bounded above by 1 and bounded below by -1.