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Mathematics 19 Online
OpenStudy (anonymous):

why sin1/x is treated as bounded function?

OpenStudy (anonymous):

think about the values c cannot be?

OpenStudy (anonymous):

i mean x

OpenStudy (anonymous):

now compare it to a normal sinx graph

OpenStudy (anonymous):

because even though 1/x is unbounded when approaching 0, the sine function itself is bounded.

OpenStudy (anonymous):

hey joemath

OpenStudy (anonymous):

\[\sin(junk)\] will always be bounded @hahd yo :)

OpenStudy (anonymous):

@joe come on chat

OpenStudy (anonymous):

If you think about sin as the \(y\) component of an arm on a unit circle, regardless of the angle the \(y\) component will always be between \(-1\) and \(1\)

OpenStudy (anonymous):

So the function is bounded above by 1 and bounded below by -1.

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