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Mathematics 7 Online
OpenStudy (anonymous):

(factor) 5y^2-14y-3 thanks

OpenStudy (anonymous):

\[(5y+1)(y-3)\] Need to know how to get there?

OpenStudy (anonymous):

yes please thanks

OpenStudy (anonymous):

5y^(2)-14y-3 Find the factors such that the product of the factors is the trinomial 5y^(2)-14y-3. This can be done by trial and error and checked using the FOIL method of simplifying polynomials. (5y+1)(y-3)

OpenStudy (anonymous):

5y^(2)-14y-3 Find the factors such that the product of the factors is the trinomial 5y^(2)-14y-3. This can be done by trial and error and checked using the FOIL method of simplifying polynomials. (5y+1)(y-3)

OpenStudy (anonymous):

5y^(2)-14y-3 Find the factors such that the product of the factors is the trinomial 5y^(2)-14y-3. This can be done by trial and error and checked using the FOIL method of simplifying polynomials. (5y+1)(y-3)

OpenStudy (anonymous):

Here's how to avoid trial and error: You want to find which two numbers multiply to equal -15 (a times c) and when added equal -14 (your b value). Those two numbers are -15 and +1. Do you follow so far?

OpenStudy (anonymous):

rogster help me

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