Question

f(x,y)= ((x+((y))))

Answer 1

\[\sqrt{x+\sqrt{y}}\]

Answer 2

what is the question?

Answer 3

what is the domain... f(x,y)=\[\sqrt{x+\sqrt{y}}\]

Answer 4

So when dealing with square roots, you never want the inside to be negative.

Looking at the y, because its nestled in a square root by itself, the first thing you want to note is that:
\[y \geq 0\]in other words, y has to be 0, or positive, cant be negative.

Now, we want:
\[x+\sqrt{y} \geq0\] as well, because of that square root on the outside. so that gives:
\[x+\sqrt{y} \geq 0 \iff x \geq \sqrt{y} \geq 0\]

Answer 5

i can the solve the exercise, but I'm not sure, besides that I have bad graphed: (

Answer 6

can you do the graphic?

Answer 7

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