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Find the inverse: y=x^2+2x+1 please :)
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replace x by y and y by x x = y^2 + 2y + 1 x = (y+1)^2 y+1 = +/- sqrt(x) \[y=-1\pm \sqrt{x}\] replace y by \[y ^{-1} = -1\pm \sqrt{x}\]
read it as y inverse
ah beautiful! thank you.
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