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how many grams of K2SO4 molar mass=174 g/mol would be needed to prepare 4.00 L of a 0.0510 M solution?
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the answer is 35.5 i found out, but does anyone know how to get that
ok
i need like the work showed
ok !!
10.00 mL of potassium was diluted to make exactly 250.00 mL of solution, this should give you a starting point.
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you got that from chacha
yes
im stuck on that.
0.051*4*174 = 35.496g
each litre should contain exactly 0.051 moles of of K2SO4 which should weigh 174*0.051
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thank you!!
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