Question

what is the domain f(x,y)= ((1-x^2-5y^4))

Answer 1

are there supposed to be any square roots? last time in your problem you had a bunch of parenthesis, but they were really square roots.

Answer 2

Ok :) i do the square :) wait me

Answer 3

\[\sqrt{1-x^2-5y^4}\]

Answer 4

Same idea as last time. We dont want the inside of that square root to be negative. so we want:
\[1-x^2-5y^4 \geq 0 \iff 1\geq x^2+5y^4\]from there I dont really see where to go with it, let me think about it for a sec.

Answer 5

please I'd appreciate it a lot

Answer 6

i wait :) dont worry

Answer 7

i guess maybe I could solve for y...that would give us:
\[x^2+5y^4 \leq 1 \iff 5y^4\leq 1-x^2\iff y^4 \leq \frac{1-x^2}{5}\]\[\iff y \leq \sqrt[4]{\frac{1-x^2}{5}}\]

Answer 8

why you change the sense > to <

Answer 9

i undersand :)

Answer 10

iam graphicing :)wait me

Answer 11

do you know how graphic' :(