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X^-2 = (2+or-square root of 3)
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Re-write the negative exponent as a fraction, then take the reciprocal of both sides and raise both sides to the 1/2 power.
is there any way you could draw it out
I can get you started.
thad be great
\[\large x^{-2} = 2 \pm \sqrt{3}\]\[\large \implies \frac{1}{x^2} = 2\pm \sqrt{3}\]\[\implies x^2 = \frac{1}{2\pm \sqrt{3}}\]\[\implies x^2 = \frac{1}{2\pm \sqrt{3}} \cdot \frac{2 \mp \sqrt{3}}{2\mp \sqrt{3}}\]\[\implies x^2 = \frac{2\pm \sqrt{3}}{4-3} = \frac{2 \pm \sqrt{3}}{1} = 2 \pm \sqrt{3}\]\[\implies x = \pm \sqrt{2 \pm \sqrt{3}}\]
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Actually that's all of it.
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