Mathematics
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OpenStudy (anonymous):
What is the equation of the line that passes through the point (1, 6) and has a slope of 3?
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OpenStudy (anonymous):
Start with the point slope formula: point (h,k), slope m
\[y-k = m(x-h)\]
OpenStudy (anonymous):
in your case the point (h,k) = (1,6)
OpenStudy (anonymous):
and the slope m = 3
OpenStudy (anonymous):
y-6=3(1-k)
OpenStudy (anonymous):
Close! but you mixed up the m(x-h) part.
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OpenStudy (anonymous):
you got the m plugged in right, but not the h, and you lost your x
OpenStudy (anonymous):
The way i was taught was y- y1=m(x-x1
OpenStudy (anonymous):
y-6=3(x-1)
OpenStudy (anonymous):
Yes, that's right. I just call y1 k, and x1 h cause some people find that less confusing.
OpenStudy (anonymous):
y-6=3x-3 Distributed
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OpenStudy (anonymous):
Yep. Then add 6 to both sides.
OpenStudy (anonymous):
y-6=3x-3
+6 +6
y=3x-3
OpenStudy (anonymous):
y= 3x-3
OpenStudy (anonymous):
mixed up the sign. it should be y = 3x + 3
OpenStudy (anonymous):
I have another question im having trouble with
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OpenStudy (anonymous):
x - 3 > -9 and 3x 15
OpenStudy (anonymous):
3x <= 15
OpenStudy (anonymous):
Ok first one first.
OpenStudy (anonymous):
add 3 to both sides of the inequality.
OpenStudy (anonymous):
x >-6
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OpenStudy (anonymous):
3x <= 15
--- ---
3 3
x <= 5
OpenStudy (anonymous):
x <= 5
OpenStudy (anonymous):
Right
OpenStudy (anonymous):
On a number line which way would they travel and open circle or close circles?