Question

Can someone please explain and show me?
write the slope intercept equation for the line that passes through (-5,-8) and is Perpendicular to,
10x - 6y= -11

Answer 1

\[10x - 6y= -11\]
\[6y = 10x+11\]
\[y = \frac53x+\frac{11}{6}\]
Now perpendicular lines have inversive gradients. Thus the gradient of the new line is \[\frac35\]
Thus our new line is:
\[y = \frac35x+c\]
Substitute in the new point
\[-8 = \frac35(-5)+c\]
\[-8 = -3+c\]
\[c=-5\]
And the equation is \[y = \frac35x+-5\]

Answer 2

hi smart cow : )

Answer 3

agreed, except perpendicular lines must have opposite reciprocal slopes
m = -3/5

hi loraaine

Answer 4

the slope of the given equation is 5/3 right? ........ the slope of perpendicular line must be opposite sign and reciprocal of that slope --> m = -3/5

Answer 5

follow rspencer's steps, except put the negative sign in there :)

Answer 6

m=-3/5

Answer 7

Oops, my bad

Answer 8

oh m is notation for slope of a line................"y=mx+b"

Answer 9

thanks STAR~~MASTER!!