Question

Find the value of the square root of 8 over 3 times the square root of 4. in simplest form.

6

2 over 3.

the square root of 2 over 3.

3 times the square root of 2.

Answer 1

\[\frac{\sqrt{8}}{3}\sqrt{4}=\frac{\sqrt{32}}{3}=\frac{\sqrt{16*2}}{3}=\frac{4\sqrt{2}}{3}\]

Answer 2

i think they mean
\[\frac{\sqrt 8}{3\sqrt4}\]

Answer 3

Hard to read. Will correct :)

Answer 4

also, it is better to explain what you did than to give the answer

Answer 5

\[\frac{\sqrt{8}}{3\sqrt{4}}\]
Times by sqrt 4 on top and bottom:
\[\frac{\sqrt{32}}{3*4}=\frac{\sqrt{16*2}}{12}=\frac{4\sqrt{2}}{12}\]
Simplify by dividing numerator and denominator by 4:
\[\frac{\sqrt{2}}{3}\]

Answer 6

note that \[\sqrt 8 = \sqrt{4 \times 2} = \sqrt 4 \times \sqrt 2\]

Answer 7

Not to be picky but the steps were there. If I skipped straight to the answer you'd see just an answer like other posts.

Answer 8

I agree that it could be clarified more but people are welcome to ask questions of explanations given.

Answer 9

yes thats true :)

Answer 10

√2 = a/b
so 2 = a2/b2
so 2b2 = a2
This means that a2 is even, and so a must be even.
So we can replace a by 2c.
so 2b2 = (2c)2
so 2b2 = 4c2
so b2 = 2c2

Answer 11

is it write

Answer 12

andremon