The speed of the car travelling up a hill is proportional to dv/ds, where v is the speed and s is the distance from the foot of the hill. (v is directly proportional to dv/ds). The car was initially travelling at 40m/s. When the car is 100m from the foot of the hill, it travels at 30m/s. Find the speed of the car when it was 50m from the foot of the hill.

Question

anonymous · Answer

Yeah, we're not gonna do your homework for ya. Please slow down and work with tutors on one problem at a time.

anonymous · Answer

its not my h/w

amistre64 · Answer

i cant parse the question to determine how to solve it ...

amistre64 · Answer

any ideas what its talking about?

anonymous · Answer

why is v speed and not velocity wtf?

amistre64 · Answer

.... right?  just doesnt make sense

anonymous · Answer

I think her teacher just confused the two...

anonymous · Answer

no he didnt

amistre64 · Answer

well, its your question; could you clarify what its talking about any?

anonymous · Answer

v=kdv/ds

amistre64 · Answer

velocity = acceleration times a constant?

anonymous · Answer

it can't be that lol it looks like a differential sort of

dy=f'(x)dx