Is this a valid strategy for graphing an inverse trigonometric function?:

Say we have f(x) = 1/2sec(x-pi/6)
To graph this, I graph g(x) = 1/2cos(x-pi/6) and then I draw out the secant graph with this.

Question

Is this a valid strategy for graphing an inverse trigonometric function?:

Say we have f(x) = 1/2sec(x-pi/6)
To graph this, I graph g(x) = 1/2cos(x-pi/6) and then I draw out the secant graph with this.

anonymous · Answer

How I graph out the secant would be by taking wherever the cosine function had x-intercepts, and making those the vertical asymptotes of the secant function.

amistre64 · Answer

ride along the humps of the cosine....

amistre64 · Answer

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anonymous · Answer

Haha!