Question

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 96 miles per hour. Train A passes a station at 11:25 A.M. If train B passes the same station at 11:40 A.M., at what time will train B catch up to train A?

Answer 1

help me please

Answer 2

no

Answer 3

jk, i will help

Answer 4

basically what we can do here is set up a system of equations

Answer 5

okay.

Answer 6

now we will work with this equation: D=R*T

Answer 7

Distance=Rate*Time

Answer 8

Okay. so.....

Answer 9

now, the distance traveled by A when B catches up is modeled by the equation: 80*T

Answer 10

im not sure how to set it up

Answer 11

for traveled distance?

Answer 12

yes

Answer 13

now the distance traveled by B when it catches up is, remeber is i15 minutes behind, can be modeled by: 96*(T-0.15)

Answer 14

now we have two equations:

80*T

and

96*(T-0.15)

Answer 15

0.15... so would one hour be 0.60

Answer 16

i mean 96*(T-0.25) sorry

Answer 17

so, we have two equations :

80*T and 96*(T-0.25)

Answer 18

okay

Answer 19

now we are looking for the point at which these two trains meet, to determine this we set both equations equal to each other, like so:

:80*T =96*(T-0.25)
that means:
80T=96T-24

Answer 20

Now with this equation: 80T=96T-24
lets subtract 96T from both sides:

-16T=-24, now divide both sides by -16 and get:

T=(-24)/(-16)=(3)/(2)

Answer 21

or 1.5 hours, that means the two trains meet 1hour and 30 min after train A passes the station

Answer 22

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