Question

Need help w/ some substitution...

The integral (x+1)sqrt(2x+x^2)dx

Answer 1

\[\int\limits_{}^{}(x+1)\sqrt{2x+x^2}dx\]

Answer 2

That might help...

Answer 3

u=2x+x^2
du=2+2xdx
du/2=1+xdx
integral of 1/2sqrt(u)du=2/3(1/2)u^3/2
1/3(2x+x^2)^3/2+C

Answer 4

I would set U = to 2x + \[x^{2}\]. You can then solve for x using that equation and plug it in where the (x+1) goes

Answer 5

that didnt work out its supposed to be going down and easier to read sorry

Answer 6

1/3(2x+x^2)^3/2+C

Answer 7

Oh it's okay, I can figure out what you did :)
Thanks!

Answer 8

welcome