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Let x-2y-z=-2 and -2x+4y+z=5 be two planes. Find the parametric equations for the line in which x-2y-z=-2 and -2x+4y+z=5 intersect.
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Anybody can help me?!
find the normal vectors for the two planes find the cross product then find any point that lies in both planes form equation I get \[(2,1,0)t+(-3,0,-1)\]
how to find normal vectors?
take the coefficients from the equations of the planes x-2y-z=-2 and -2x+4y+z=5 (1,-2,-1) and (-2,4,1)
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