Question

how do i test the symmetry of the equation y=X^2-2 ?

Answer 1

is function even or odd?

Answer 2

its even

Answer 3

really?

Answer 4

f(-x)=(-x^2)-2

Answer 5

yes it is even correct

Answer 6

so its symmetrical about y axis

Answer 7

that was ur test

Answer 8

oh it says i need to test for the symetrys by settin xto-x for y teest, yto -y for x test and both - for origin but which one is my answer

Answer 9

A graph will have symmetry about the x-axis if we get an equivalent equation when all the y’s are replaced with y.

A graph will have symmetry about the y-axis if we get an equivalent equation when all the x’s are replaced with x.

A graph will have symmetry about the origin if we get an equivalent equation when all the y’s are replaced with y and all the x’s are replaced with x

Answer 10

setting x to -x is answer

Answer 11

when looking at the ex equation i change it -y=X^-2 to test for x axis symetry then wat?

Answer 12

no change y to f(x) as then u can set it to f(-x)=(-x)^2-2

Answer 13

making equation even the same as original f(x)=x^2-2

Answer 14

u lost me lol

Answer 15

book says graph symmetric with respect to y axis if replacing x by -x wields equiv equation

Answer 16

doesnt say F(-x)