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You deposit $3500 in an account that pays 4.5% annual interest, compounded monthly. How long will it take for the balance to reach 5,000?
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solve \[5000=3500(1+\frac{.045}{12})^{23t}\] for t.
typo
\[5000=3500(1+\frac{.045}{12})^{12t}\]
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divide by 3500 get \[\frac{10}{7}=(1.00375)^{12t}\]
our answer will not be precise because .045/12 is a repeating decimal, but we will be close
solve \[\frac{10}{7}=(1.00375)^{12t}\] via \[\ln(\frac{10}{7})=12t\ln(1.00375)\] \[t=\frac{\ln(\frac{10}{7})}{12\ln(1.00375)}\]
now a calculator
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